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How much interest would a person earn on a $34,000 investment at 6% interest compounded annually for 9 years? What would be the total amount at the end of that time?

A) $23,144 in interest; $57,144 total
B) $22,144 in interest; $56,144 total
C) $21,024 in interest; $55,024 total
D) $20,240 in interest; $54,240 total

User Aquilesb
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1 Answer

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Final answer:

After calculating the compound interest for a $34,000 investment at 6% interest compounded annually for 9 years, the total amount would be approximately $57,442.26, with the interest earned at about $23,442.26. The closest provided option to this result is A) $23,144 in interest; $57,144 total.

Step-by-step explanation:

Calculating Compound Interest

To find out how much interest a person would earn on a $34,000 investment at 6% interest compounded annually for 9 years, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the amount of money accumulated after n years, including interest.

P is the principal amount (the initial amount of money).

r is the annual interest rate (decimal).

n is the number of times that interest is compounded per year.

t is the time the money is invested for, in years.

In this case, P = $34,000, r = 6% or 0.06, n = 1 (since it is compounded annually), and t = 9.

Plugging the numbers into the formula:

A = $34,000(1 + 0.06/1)^(1*9)

A = $34,000(1 + 0.06)^9

A = $34,000(1.06)^9

A = $34,000 * 1.6894781

A ≈ $57,442.26

The total interest earned is the final amount minus the original principal:

Interest = A - P

Interest ≈ $57,442.26 - $34,000

Interest ≈ $23,442.26

So, the total amount at the end of 9 years would be approximately $57,442.26, with the interest earned being about $23,442.26. Therefore, the closest answer from the provided options is A) $23,144 in interest; $57,144 total, although the exact calculation gives us a slightly different figure.

User Bart S
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