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What is the volume in ml of 492 g of nitric acid with a specific gravity of 1.40?

a) 350.71 ml
b) 492 ml
c) 350 ml
d) 700.80 ml

1 Answer

3 votes

Final answer:

The volume of 492 g of nitric acid with a specific gravity of 1.40 is calculated by dividing the mass of the nitric acid by its density. The volume comes out to be 351.43 ml, and the closest answer choice is 350 ml.

Step-by-step explanation:

To find the volume in milliliters (ml) of 492 g of nitric acid with a specific gravity of 1.40, we first recognize that specific gravity is the ratio of the substance's density compared to the density of water. Because the comparison is with water and its density is 1 g/ml at 4°C, the specific gravity of a substance is numerically equivalent to its density in g/ml. Therefore, the density of nitric acid is 1.40 g/ml.

Next, we use the formula:

Density = mass / volume

Rearranging this formula to solve for volume gives us:

Volume = mass / density

So the volume of the nitric acid in ml can be calculated as follows:

Volume = 492 g / 1.40 g/ml = 351.43 ml

Therefore, the closest answer from the options provided is:

(c) 350 ml.

User Rohan Saxena
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