Question

For the chemical reaction H₂ (g) + F₂ (g) → 2 HF (g) ∆H° = -79.2 kJ/mol. What is the molar enthalpy (in kJ/mol) for the reaction 3 H₂ (g) + 3 F₂ (g) → 6 HF (g)

Answer 1

Answer: -237.6

Step-by-step explanation:

Multiplying both sides of the equation by 3 means you multiply the molar enthalpy by 3.