Final answer:
The chemical reaction between alcohol, NaOCl, and CH₃COOH results in the formation of sodium acetate, sodium ion, water, and chloride ion.
Step-by-step explanation:
The chemical reaction between alcohol, NaOCl, and CH₃COOH can be represented as follows:
CH₃OH + NaOCl + CH₃COOH → CH₃COO⁻ + Na⁺ + H₂O + Cl⁻
In this reaction, the ethyl alcohol (CH₃OH) reacts with sodium hypochlorite (NaOCl) and acetic acid (CH₃COOH) to form sodium acetate (CH₃COO⁻), sodium ion (Na⁺), water (H₂O), and chloride ion (Cl⁻).
The primary reactants are alcohol (CH₃OH), sodium hypochlorite (NaOCl), and acetic acid (CH₃COOH).
The resulting products are sodium acetate (CH₃COO⁻), sodium ion (Na⁺), water (H₂O), and chloride ion (Cl⁻).