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6. What is the displacement of an object whose velocity-time graph is shown below? A. 50 m +10 0 -10 B. 25 m C. 10 m 5 D.0 m​

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The displacement of the object, as calculated from the area under a velocity-time graph showing constant acceleration, is 75 meters.

To determine the displacement of an object from a velocity-time graph, you can calculate the area under the graph line.

A velocity vs. time graph starting at 0 and ending at 10 m/s over a span of 15 seconds represents a straight line which indicates constant acceleration.

The area under this line is a triangle with a base of 15 seconds (t) and a height of 10 m/s (v), giving us an area of 1/2 * base * height = 1/2 * 15 s * 10 m/s = 75 m.

Therefore, the object's net displacement is 75 meters.

6. What is the displacement of an object whose velocity-time graph is shown below-example-1
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