Question

Given the following Fraction object, write a conversion operator that returns a float value of the fraction by dividing the first parameter by the second parameter, converting them both into floats.

a) Fraction operator float() { return static_cast(numerator) / static_cast(denominator); }
b) float operator() { return static_cast(numerator) / static_cast(denominator); }
c) Fraction operator_cast() { return static_cast(numerator) / static_cast(denominator); }
d) Fraction operator float_cast() { return static_cast(numerator) / static_cast(denominator); }

Answer 1

The correct option for converting a Fraction object to a float is by using a conversion operator with the syntax 'float operator float() const', which divides the integer numerator and denominator after casting them to floats.

Step-by-step explanation:

When a conversion operator is used in object-oriented programming, specifically in C++, it allows an object to be converted to a different type. In the case of the Fraction object, which likely has an integer numerator and denominator, the goal is to convert the Fraction into a float. The correct syntax for a conversion operator in C++ to convert a user-defined type to a float would use operator float() and look like this:

float operator float() const {
return static_cast(numerator) / static_cast(denominator);
}

This allows the Fraction object to be implicitly converted to a float when necessary, such as in arithmetic operations or assignments. The syntax involves the operator keyword followed by the desired target type (float in this case), and the function body performs the conversion using static_cast to convert the integer values into floats before division.