135k views
5 votes
How many more times dense is the air in a balloon at 4 ATM/bar compared to the air density at the surface?

a. 2 times denser
b. 3 times denser
c. 4 times denser
d. 5 times denser

1 Answer

0 votes

Final answer:

The density of air in a balloon at 4 ATM/bar is 4 times denser than the air density at the surface. To determine the density of the air in the balloon, we can use the ideal gas law equation: PV = nRT, The air in the balloon at 4 ATM/bar is 4 times denser than the air at the surface.

Step-by-step explanation:

The density of air in a balloon at 4 ATM/bar is 4 times denser than the air density at the surface. To determine the density of the air in the balloon, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

density of air in a balloon at 4 ATM/bar is 4 times denser than the air density at the surface. To determine the density of the air in the balloon, we can use the ideal gas law equation: PV = nRT, The air in the balloon at 4 ATM/bar is 4 times denser than the air at the surface. Since the pressure is 4 times higher in the balloon (4 ATM), the density of the air in the balloon will also be 4 times higher compared to the air density at the surface.

User Andrew Stone
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.