Question

Assume input is a char array holding a C-string. Write code that counts the number of elements in the array that contain an alphabetic character.

Answer 1

To count the number of alphabetic characters in a C-string, iterate over each element and use the isalpha() function to check for alphabetic characters.

Step-by-step explanation:

To count the number of elements in the char array that contain an alphabetic character, you can iterate over each element of the array and check if it is an alphabetic character using the isalpha() function from the cctype library in C++. If a character is alphabetic, you increment a counter variable. Here's an example:

#include <cctype>
#include <iostream>

int countAlphabeticChars(char arr[], int size) {
int count = 0;
for (int i = 0; i < size; i++) {
if (std::isalpha(arr[i])) {
count++;
}
}
return count;
}

int main() {
char input[] = "Hello123";
int size = sizeof(input) - 1; // Exclude null terminator
int alphabeticCount = countAlphabeticChars(input, size);
std::cout << "Number of alphabetic characters: " << alphabeticCount << std::endl;
return 0;
}