Question

"Look at the following code. What value will be stored in s after the code executes?

char name[10];
int s;
strcpy(name, ""Jimmy"");
s = strlen(name);"

A) 5
B) 6
C) 4
D) 10

Answer 1

The value stored in 's' after the code executes is 5.

Step-by-step explanation:

The value stored in s after the code executes is 5.

In the given code, a character array name is declared with a size of 10. The string "Jimmy" is copied into the name using the strcpy() function. The strlen() function is then used to determine the length of the string stored in the name and assign it to the variable s.

So, after the execution of the code:

The name array contains the string "Jimmy" followed by null characters to fill the remaining space in the array.

The s variable is assigned the length of the string stored in name, which is 5.

The correct answer is A) 5, as the length of the string "Jimmy" is 5 characters.