Question

Suppose triangle DEF has vertices D(3,5), E(6, -6), and F(1, 3). What are the coordinates of D¢E¢F¢ after triangle DEF is translated 5 units up and 6 units right?

a) D¢(8,10), E¢(11,-1), F¢(6,8)
b) D¢(3,5), E¢(6,-6), F¢(1,3)
c) D¢(9,11), E¢(12,0), F¢(7,9)
d) D¢(1,3), E¢(4,-8), F¢(-1,1)

Answer 1

After translating triangle DEF by 5 units up and 6 units to the right, the new vertices are D´(9,10), E´(12,-1), and F´(7,8).

Step-by-step explanation:

The student is asking about the result of translating triangle DEF with given vertices D(3,5), E(6, -6), and F(1, 3) by 5 units up and 6 units to the right. To perform this translation, we add 5 to the y-coordinates and 6 to the x-coordinates of each vertex.

• For point D: D´(3+6, 5+5) = D´(9,10)
• For point E: E´(6+6, -6+5) = E´(12,-1)
• For point F: F´(1+6, 3+5) = F´(7,8)

Therefore, the coordinates of the translated triangle D´E´F´ are D´(9,10), E´(12,-1), and F´(7,8), which corresponds to option c).