Question

A NASA spacecraft landed on the surface of Thund with an average orbital speed of 24 maard (0.002435 meters per second). What is this speed in meters per hour?

a) 0.002435 meter per second

b) 0.2436 meter per hour

c) 2.460 meters per hour

d) 24.350 meters per second

Answer 1

The speed of the NASA spacecraft on the surface of Thund is 8.766 meters per hour. The correct answer is 8.766. The correct answer is c) 2.460 meters per hour.

Step-by-step explanation:

To convert the average orbital speed from meters per second to meters per hour, we need to multiply the given speed by the number of seconds in an hour.

There are 3600 seconds in an hour. So, the conversion factor is 3600.

Given speed = 0.002435 meters per second

Speed in meters per hour = 0.002435 meters per second x 3600 seconds = 8.766 meters per hour

Therefore, the speed of the NASA spacecraft on the surface of Thund is 8.766 meters per hour.

The correct answer is 8.766 .

Therefore, the correct answer is c) 2.460 meters per hour.