Question

In 2018, the James H. Miller coal-fired power plant in Alabama was the largest emitter of CO₂ in the country, with 1.84 × 10^8 kg emitted per year. (For comparison, the total amount emitted by automobiles in 2018 was 1.14 × 10^12 kg per year). The molar mass of CO₂ is 44.01 g/mol. How many moles of CO₂ is emitted by this plant? 1841.

Answer 1

The James H. Miller coal-fired power plant in Alabama emitted approximately 4.18 × 10⁹ moles of CO₂ in 2018, calculated by converting the mass of the emitted CO₂ to grams and then dividing by the molar mass of CO₂.

Step-by-step explanation:

The question involves calculating the number of moles of CO₂ emitted by the James H. Miller coal-fired power plant in Alabama. Given that the plant emitted 1.84 × 10⁸ kg of CO₂ in a year and knowing the molar mass of CO₂ is 44.01 g/mol, we can perform the calculation as follows:

First, we need to convert the mass of CO₂ from kilograms to grams:

• 1.84 × 10⁸ kg CO₂ × 1000 g/kg = 1.84 × 10¹¹ g CO₂

Now we can calculate the moles of CO₂:

• Number of moles = Mass of CO₂ / Molar mass of CO₂
• Number of moles = 1.84 × 10¹¹ g CO₂ / 44.01 g/mol
• Number of moles ≈ 4.18 × 10⁹ moles of CO₂

Therefore, the James H. Miller coal-fired power plant emitted approximately 4.18 × 10⁹ moles of CO₂ in 2018.