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Find the equation of a line passing through the point (3,1) and parallel to y = (2/3)x + 1:

A. y = (-5/3)x - (2/3)
B. y = -x - (2/3)
C. y = (2/3)x - 1
D. y = (-2/3)x - 1

User Dcbyers
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1 Answer

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Final answer:

The equation of a line parallel to y = (2/3)x + 1 and passing through the point (3,1) is y = (2/3)x - 1, which is option C.

Step-by-step explanation:

To find the equation of a line passing through the point (3,1) and parallel to y = (2/3)x + 1, we need to realize that parallel lines have the same slope. The given line has a slope of 2/3. Since the line we want to find is parallel to this, its slope must also be 2/3.

To find the equation of our line, we use the point-slope form of a line, which is y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point the line passes through. Plugging in our values we get y - 1 = (2/3)(x - 3).

Let's simplify the equation:

  • y - 1 = (2/3)x - 2
  • y = (2/3)x - 2 + 1
  • y = (2/3)x - 1

The correct equation is therefore y = (2/3)x - 1, which is option C.

User HeshanHH
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