Based on the concept of combinations, the probability that a randomly selected jury of 12 people is all male is approximately 0.0000181, or 0.00181%.
The total number of the jury pool = 35
The number of men = 12
The number of women = 23
The total number of ways to choose 12 people from a pool of 35 is given by the combination formula:
![[ \text{Total combinations} = \binom{35}{12} ]](https://img.qammunity.org/2024/formulas/mathematics/college/qwcxw5b0laurbzlvb5xzp7uleho973l4zq.png)
The number of ways to choose 12 men from 12 men is given by the combination formula:
![[ \text{Combinations of 12 men} = \binom{12}{12} ]](https://img.qammunity.org/2024/formulas/mathematics/college/6tkbrk50mynwitj7pcwugtvu22u2rej5go.png)
The probability of selecting 12 men is then given by the ratio of the number of ways to choose 12 men to the total number of combinations:
![[ \text{Probability} = \frac{\binom{12}{12}}{\binom{35}{12}} ]](https://img.qammunity.org/2024/formulas/mathematics/college/xhcg7els1n95lngtbjuqc1z3zkfpthtac7.png)
Evaluating this expression gives us the probability that a randomly selected jury of 12 people is all male.
![[ \text{Probability} = \frac{1}{\binom{35}{12}} ]](https://img.qammunity.org/2024/formulas/mathematics/college/guw419hh8307tvlhge4cjnr9v3g9l0ar20.png)
The total number of combinations is given by:
![[ \binom{35}{12} = (35!)/(12!(35-12)!) = 5,527,071 ]](https://img.qammunity.org/2024/formulas/mathematics/college/86cjsuy1oeasml6aam5hxtcmjqw3d8iu4u.png)
The number of ways to choose 12 men from 12 men is given by:
![[ \binom{12}{12} = (12!)/(12!(12-12)!) = 1 ]](https://img.qammunity.org/2024/formulas/mathematics/college/ca9b1edw6p0hgl14bkxb4lm0lzd0w99x1f.png)
So, the probability of selecting 12 men from the pool is:
![[ \text{Probability} = (1)/(5,527,071) \approx 0.000000181 ]](https://img.qammunity.org/2024/formulas/mathematics/college/trupb8eknga20h29tvfai4c59bmpbkl998.png)
Thus, the probability that a randomly selected jury of 12 people is all male is approximately 0.0000181, or 0.00181%.