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A 4.1 μC point charge is placed in an external uniform electric field that has a magnitude of 69000 N/C. What is the electric force acting on the point charge? Write your answer with the unit.

a) 283.5 N
b) 0.2835 N
c) 169.4 N
d) 1.694 N

User Rejeesh
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1 Answer

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Final answer:

The electric force on a 4.1 µC charge in a 69000 N/C electric field is calculated using the formula F = qE, resulting in a force of 0.2835 N. The correct answer is b) 0.2835 N.

Step-by-step explanation:

The electric force acting on a point charge in a uniform electric field can be calculated by the formula F = qE, where F is the electric force, q is the charge, and E is the electric field strength. For a 4.1 µC charge (which is 4.1 × 10-6 C) in an electric field of 69000 N/C, the electric force is found by multiplying the charge by the electric field strength:

F = (4.1 × 10-6 C)(69000 N/C) = 0.2835 N.

Therefore, the correct answer is b) 0.2835 N.

User Abhishek Ringsia
by
8.2k points
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