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At noon, it was -18°F in Billings, MT. At the same time, it was 42°F in Mesa, Arizona. How much warmer was Mesa than Billings, Montana?

a. 24°F
b. 60°F
c. 18°F
d. 30°F

User Loetn
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1 Answer

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Final answer:

To find the temperature difference, subtract the temperature in Billings (-18°F) from the temperature in Mesa (42°F), resulting in a 60°F difference. Mesa was 60°F warmer than Billings.

Step-by-step explanation:

The question asks how much warmer it was in Mesa, Arizona compared to Billings, Montana, if at noon, it was -18°F in Billings and 42°F in Mesa. Calculating the difference in temperature between the two locations involves subtracting the lower temperature (Billings) from the higher temperature (Mesa).

42°F (Mesa) - (-18°F) (Billings) = 42°F + 18°F = 60°F.

Therefore, the answer is 60°F, which means Mesa was 60°F warmer than Billings.

User Hsn
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