Question

You accelerate from a velocity of +4 m/s to +13 m/s over a displacement of 300 m. What is your acceleration during this time?

a) 1.5 m/s²
b) 2.0 m/s²
c) 2.3 m/s²
d) 3.0 m/s²

Answer 1

The average acceleration during this time is 0.525 m/s².

Step-by-step explanation:

The average acceleration during this time can be calculated using the formula:

acceleration = (change in velocity)/(change in time)

Given that the initial velocity u is +4 m/s, the final velocity v is +13 m/s, and the displacement d is 300 m, the change in velocity is 13 m/s - 4 m/s = 9 m/s and the change in time is the displacement divided by the average velocity:

change in time = displacement/average velocity = 300 m/((u+v)/2)

Substituting the values, we have:

change in time = 300 m/((4 m/s + 13 m/s)/2) = 300 m/(17.5 m/s) = 17.14 s

Now, we can calculate the average acceleration:

average acceleration = (9 m/s)/(17.14 s) = 0.525 m/s²

So, the correct answer is 0.525 m/s².