Final answer:
The mass of 6.02 × 10²³ molecules of calcium carbonate is 200 g.
Step-by-step explanation:
The molar mass of calcium carbonate (CaCO3) is calculated by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms. The atomic masses of Ca, C, and O are 40.08 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively. Therefore, the molar mass of CaCO3 = 40.08 + 12.01 + (16.00 x 3) = 40.08 + 12.01 + 48.00 = 100.09 g/mol. Given that 1 mole of CaCO3 contains 6.02 x 1023 molecules, we can use this information to calculate the mass of 6.02 x 1023 molecules of CaCO3. Mass = (6.02 x 1023 molecules) x (100.09 g/mol) = 6.02 x 1023 x 100.09 g = 6.02 x 1025 g.
Therefore, the correct answer is 200 g (option c).