Final answer:
The range of the diver who jumps off with a velocity of 2.8 m/s and lands in the water 2.6 seconds later is calculated as the product of velocity and time, which gives 7.28 m.
Step-by-step explanation:
The subject of the question is Physics as it involves the principles of motion and kinematics. We are asked to calculate the range of a diver who jumps off a high-diving platform with an initial velocity and lands in the water a known time later. Range here refers to the horizontal distance traveled by the diver from the point of the jump until hitting the water. Since the diver jumps with a horizontal velocity of 2.8 m/s and is in the air for 2.6 seconds, the range can be calculated using the formula:
Range = velocity × time
Range = 2.8 m/s × 2.6 s = 7.28 m
Therefore, the correct answer is (b) 7.28 m.