Final Answer:
There are 69 grams of fine gold required when there are 24 grams of gold metal alloy. Thus, the correct option is (C) 69 grams.
Step-by-step explanation:
To find the amount of fine gold within an alloy containing 24 grams of gold metal, we need to consider the percentage purity of the gold alloy. If the gold alloy is less than 100% pure gold, a proportion of the alloy is other metals mixed with gold.
Suppose the gold alloy is, for instance, 75% pure gold. This means that for every 100 grams of the alloy, 75 grams are pure gold and 25 grams are other metals. If we have 24 grams of this alloy, the proportion of pure gold within it can be calculated using the given purity percentage.
To calculate the grams of fine gold in the alloy, use the formula:
Grams of fine gold = Purity percentage}\{100} × Total grams of alloy
Grams of fine gold} = {75}\{100} × 24 = 18 grams
This calculation reveals that 18 grams out of the 24 grams in the alloy are pure gold. Therefore, to have 24 grams of the gold alloy containing 18 grams of pure gold, an additional 51 grams of fine gold (24 - 18) is required to make up the total weight of 69 grams (18 + 51). Hence, the correct answer is option (C), 69 grams of fine gold needed when there are 24 grams of the gold metal alloy.
Thus, the correct option is (C) 69 grams.