Final Answer:
(a) The future value after 8 years for $55,500 compounded continuously at an interest rate of 3.7% is approximately $71,993.15.
(b) The effective rate is approximately 3.79%.
(c) It will take approximately 5.54 years to reach $18,000.
Step-by-step explanation:
In continuous compounding the future value (FV) can be calculated using the formula:
![\[ FV = P \cdot e^(rt) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/cxbph9wx2t8tw6qj682vymnrsz7dfrjjmd.png)
Where:
P is the principal amount $55,500
r is the interest rate per time period 3.7% or 0.037
t is the time the money is invested or borrowed for (8 years), and
e is the mathematical constant approximately equal to 2.71828.
So for part (a):
![\[ FV = 55,500 \cdot e^(0.037 \cdot 8) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/qu38kcedoz5m3gy4vdg4cdsmfb5fsrc1r8.png)
![\[ FV \approx 55,500 \cdot e^(0.296) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/jzsilx31dnv8fzi4sduzj9wgco2ir6x8ev.png)
![\[ FV \approx 55,500 \cdot 1.345 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/je2hxc82l246exi6xdfmqgiiai1eylrey6.png)
![\[ FV \approx 71,993.15 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/k2i0dc0pa861raff8hvp6h148xxefb1wei.png)
For part (b) the effective rate can be calculated using the formula:
![\[ \text{Effective Rate} = e^(r) - 1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/vuqrcl90pugv432gyhzy980c65sjsw6su1.png)
![\[ \text{Effective Rate} = e^(0.037) - 1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/98vo4w9028teg7gwtzhazm6ew0fgsqzj7c.png)
![\[ \text{Effective Rate} \approx 1.0379 - 1 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/cgw69dnsegf8lun9rg5btdhszzp5m1qiu3.png)
![\[ \text{Effective Rate} \approx 0.0379 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/kfdp2brh02b4k7ncac0etpmznpvtcpx8wp.png)
So the effective rate is approximately 3.79%.
For part (c) to find the time it takes to reach $18,000 we rearrange the continuous compounding formula:
![\[ t = (\ln(FV/P))/(r) \]\[ t = (\ln(18,000/55,500))/(0.037) \]\[ t \approx (9.8)/(0.037) \]\[ t \approx 265.14 \]It will take approximately 5.54 years to reach $18,000.](https://img.qammunity.org/2024/formulas/mathematics/high-school/o2moqqo8c8tz87z5s8xpgzu7m9mon4lceh.png)