Final answer:
The volume of 1 troy ounce of pure gold, given a mass of 31.103 grams and a density of 19.32 g/cm3, is approximately 1.61 cubic centimeters.
Step-by-step explanation:
The student is asking for the volume of 1 troy ounce of pure gold. One troy ounce of gold is equal to 31.103 grams. To find the volume, we need the density of gold, which is approximately 19.32 g/cm3. The formula to calculate volume is mass divided by density (V = m/ρ). Using this formula:
V = 31.103g / 19.32g/cm3
V ≈ 1.61 cm3
The volume of 1 troy ounce of pure gold is therefore approximately 1.61 cubic centimeters.