Final answer:
The number of different combinations when selecting 3 objects from a group of 4 without replacement is 4 combinations, which is answer A.
Step-by-step explanation:
The question asks for the number of different combinations that can be formed by selecting 3 objects from a group of 4 objects without replacement. To solve this, we use the combinations formula C(n, k) = n! / [k!(n - k)!], where 'n' is the total number of objects and 'k' is the number of objects to choose. Since we are choosing 3 objects (k = 3) from a total of 4 (n = 4), the calculation would be C(4, 3) = 4! / [3!(4 - 3)!] which equals to 4 / 1 = 4 combinations. Therefore, the answer is A) 4 combinations.