Question

The density of an alcohol is 0.788 g/mL. What volume in microliters, µl, will correspond to a mass of 20.500 mg?

a. 26.0 mL
b. 2.60 x 10⁴ mL
c. 2.60 x 10⁻2 L
d. 16.2 µl

Answer 1

The volume in microliters that corresponds to a mass of 20.500 mg of alcohol with a density of 0.788 g/mL is 26.0 µL.

Step-by-step explanation:

To find the volume in microliters corresponding to a mass of 20.500 mg of alcohol with a density of 0.788 g/mL, you can use the formula density = mass/volume. First, you convert 20.500 mg to grams since the density is given in g/mL:

20.500 mg = 0.020500 g

Next, solve for volume using the density formula rearranged as volume = mass/density:

Volume = 0.020500 g / 0.788 g/mL = 0.0260047770 mL

To convert this to microliters, recall that 1 mL is equivalent to 1000 µL, thus:

0.0260047770 mL × 1000 µL/mL = 26.0047770 µL

After rounding to three significant figures, the volume in microliters is 26.0 µL, making the answer:

d. 26.0 µL