Question

What is the magnitude of the acceleration of a ball that is dropped off the side of a cliff after 1, 2, 3, 4, 5 seconds? (assume down is positive).

a. 9.8, 9.8, 9.8, 9.8, 9.8 m/s²
b. 4.9, 9.8, 14.7, 19.6, 24.5 m/s²
c. 5, 20, 45, 80, 125 m/s²
d. 9.8, 19.6, 29.4, 39.2, 49 m/s²

Answer 1

The magnitude of the acceleration is 9.8 m/s² for each second.

Step-by-step explanation:

The magnitude of the acceleration of a ball that is dropped off the side of a cliff can be calculated using the equation:

acceleration = change in velocity/time

In this case, the change in velocity is equal to the final velocity minus the initial velocity, and the time is the total time the ball has been falling. Since the ball is only accelerating due to gravity, the acceleration is constant and equal to 9.8 m/s².

Therefore, for each second, the magnitude of the acceleration will be 9.8 m/s².

Answer 2

The magnitude of the acceleration is 9.8 m/s² for each second.

Step-by-step explanation:

The magnitude of the acceleration of a ball that is dropped off the side of a cliff can be calculated using the equation:

acceleration = change in velocity/time

In this case, the change in velocity is equal to the final velocity minus the initial velocity, and the time is the total time the ball has been falling. Since the ball is only accelerating due to gravity, the acceleration is constant and equal to 9.8 m/s².

Therefore, for each second, the magnitude of the acceleration will be 9.8 m/s².