Question

A car is going 8.9 m/s on an access road into a highway, and then accelerates at 1.3 m/s² for 2.8 seconds. How fast is it then going?

a. 12.45 m/s
b. 15.72 m/s
c. 11.02 m/s
d. 14.17 m/s

Answer 1

The final speed of the car is 12.54 m/s.

Step-by-step explanation:

To find the final speed of the car, we need to calculate the change in velocity during the acceleration period and add it to the initial velocity. The change in velocity can be found using the equation:

Δv = a * t

where Δv is the change in velocity, a is the acceleration, and t is the time.

Plugging in the values, we have:

Δv = 1.3 m/s² * 2.8 s

Calculating the change in velocity gives us:

Δv = 3.64 m/s

Adding the change in velocity to the initial velocity:

Final speed = 8.9 m/s + 3.64 m/s = 12.54 m/s

So the car is then going at a speed of 12.54 m/s.