Question

If an arrow is shot upward on the moon with a velocity of 43 meters per second, what is its height in meters after t seconds, given by the equation h(t) = 43t - 0.83t^2?

a. 43t - 0.83t^2 meters
b. 43t meters
c. 0.83t^2 meters
d. -0.83t^2 meters

Answer 1

The height of the arrow shot upward on the moon after t seconds is correctly represented by option a. 43t - 0.83t^2 meters.

Step-by-step explanation:

If an arrow is shot upward on the moon with a velocity of 43 meters per second, the height in meters after t seconds is given by the equation h(t) = 43t - 0.83t2. This equation takes into consideration the gravitational acceleration on the moon and the initial velocity of the arrow. The correct representation for the height of the arrow after t seconds is option a. 43t - 0.83t2 meters.