Question

A new Youth Sports Center is being built in Safe Harbor. The perimeter of the rectangular playing field is 246 yards. The length of the field is 3 yards less than double the width. What are the dimensions of the playing field?

(A) Length is 2 times the width minus 3 yards, Width is the original width.
(B) Length is the original width, Width is 2 times the width minus 3 yards.
(C) Length is the original width plus 3 yards, Width is 2 times the original width.
(D) Length is 2 times the original width, Width is the original width minus 3 yards.

Answer 1

To find the dimensions of the playing field, we use the perimeter formula and the given relationship between length and width. After setting up the equation and solving for width, we find that the width is 41 yards and the length is 79 yards.

Step-by-step explanation:

The question involves finding the dimensions of a rectangular playing field where the perimeter is 246 yards, and the length is described in terms of the width. We use the formula P = 2l + 2w where P is the perimeter, l is the length, and w is the width. To solve the problem, we can set up an equation where l = 2w - 3. Substituting the values into the perimeter formula, we have 2(2w - 3) + 2w = 246. Simplifying and solving for w, we get w = 41 yards and therefore l = 2(41) - 3 = 79 yards.