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Find the quotient of x^2-9x+20 and x-5

User Unkas
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27 votes

Answer: x-4

Explanation:


\displaystyle\\(x^2-9x+20)/(x-5)=\\\\(x^2-5x-4x+20)/(x-5) =\\\\((x^2-5x)-(4x-20))/(x-5) =\\\\(x(x-5)-4(x-5))/(x-5)=\\\\((x-5)(x-4))/(x-5) =\\\\x-4

User Arturtr
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