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An object's path can be modeled by the equation h(t) = -16t² + 12t + 8. At what height did the object start at?

a. 16 feet
b. 12 feet
c. 0 feet
d. 8 feet

User Ekerner
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1 Answer

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Final answer:

The initial height of the object is found by evaluating the constant term in the equation h(t) = -16t² + 12t + 8 at t = 0, which gives us 8 feet.

Step-by-step explanation:

To determine the initial height at which the object starts, we look at the given model of the object's path: h(t) = -16t² + 12t + 8. The initial height corresponds to the value of h(t) when t, the time, is zero. Plugging t = 0 into the equation, we find that the height h(0) is the value of the constant term in the quadratic equation, which in this case is 8 feet. Therefore, the object started at a height of 8 feet. In the context of projectile motion equations, the constant term represents the initial position or height. In this case, the object's initial height is 8 feet above the reference point.

User Seth Johnson
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