Question

For the four pairs of dice listed above (#1: 3, 3, 3, 3, 3, 3 #2: 4, 4, 4, 4, 0, 0 #3: 5, 5, 5, 1, 1, 1 #4: 6, 6, 2, 2, 2, 2), make a conclusion about which one of the four dice has the highest probability of winning.

a) Dice #1
b) Dice #2
c) Dice #3
d) Dice #4

Answer 1

To determine the dice pair with the highest probability of winning, we need to count the number of favorable outcomes for each pair. Dice #4 has the highest number of favorable outcomes and thus has the highest probability of winning.

Step-by-step explanation:

From the given pairs of dice, we need to determine which one has the highest probability of winning. To do this, we need to calculate the probability of each dice pair winning. The pair with the highest probability of winning will have the highest number of favorable outcomes.

1. Dice #1: 3, 3, 3, 3, 3, 3
2. Dice #2: 4, 4, 4, 4, 0, 0
3. Dice #3: 5, 5, 5, 1, 1, 1
4. Dice #4: 6, 6, 2, 2, 2, 2

To determine the probability of each pair winning, we can count the number of favorable outcomes for each pair. A favorable outcome is one in which the dice pair gives the highest total when rolled. We can observe that Dice #4 has the highest probability of winning because it has the most favorable outcomes:

• Dice #1: 0 favorable outcomes
• Dice #2: 4 favorable outcomes
• Dice #3: 3 favorable outcomes
• Dice #4: 5 favorable outcomes

Therefore, the correct answer is d) Dice #4 has the highest probability of winning.