29.6k views
0 votes
Two thousand mosquitoes are placed in a glass container into which an insecticide is sprayed. If the number of mosquitoes still alive decreases by 75% every two hours, approximately how many mosquitoes will be alive 6 hours after they were originally placed into the container?

A) 13
B) 844
C) 32
D) 27
E) 0

1 Answer

5 votes

Final answer:

After 6 hours, the mosquito population would be reduced from 2000 to approximately 31 mosquitoes. This is calculated by reducing the population by 75% every 2 hours, three times.

Step-by-step explanation:

The student is asking how many mosquitoes will be alive after 6 hours if 2000 mosquitoes are exposed to an insecticide that reduces the population by 75% every 2 hours. To solve this problem, we calculate the number of mosquitoes after each interval.

Initial population: 2000 mosquitoes

After 2 hours: 2000 × 0.25 = 500 mosquitoes

After 4 hours: 500 × 0.25 = 125 mosquitoes

After 6 hours: 125 × 0.25 = 31.25 mosquitoes

Since we can't have a fraction of a mosquito, we round down to 31 mosquitoes, which matches answer choice D).

User Klijakub
by
8.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.