162k views
1 vote
Given g(x) = x^2 - 16, what is the value of g(x) when x = 4?

A. 0
B. 12
C. 20
D. 32

User Haroldas
by
8.1k points

1 Answer

4 votes

Final answer:

To find the value of g(x) when x=4, substitute the value of x into the given equation g(x) = x^2 - 16, which results in g(4) = 16 - 16 = 0. Thus, the correct answer is A. 0.

Step-by-step explanation:

The student is asking for the value of the function g(x) when x = 4. Given that g(x) = x^2 - 16, we substitute 4 for x in the equation to find the value of g(4).

g(4) = (4)^2 - 16

g(4) = 16 - 16

g(4) = 0

Therefore, the answer is A. 0.

User Ucsarge
by
8.6k points

No related questions found