Question

A water rocket is fired into the air at 45 m/s at an angle of 35 degrees above the horizontal. Calculate the following:

A. Find the velocity along the x-axis.
B. Find the velocity along the y-axis.
C. Find the height the rocket goes.
D. Find the total time the rocket is in the air.
E. Find the distance the rocket travels.

Answer 1

The velocity along the x-axis is 37.15 m/s, the velocity along the y-axis is 25.70 m/s, the height the rocket goes is 33.09 meters, the total time the rocket is in the air is 5.25 seconds, and the distance the rocket travels is 194.44 meters.

Step-by-step explanation:

To calculate the velocity along the x-axis, we can use the equation:

Vx = initial velocity * cos(angle) = (45 m/s) * cos(35 degrees) = 37.15 m/s.To calculate the velocity along the y-axis, we can use the equation: Vy = initial velocity * sin(angle) = (45 m/s) * sin(35 degrees) = 25.70 m/s.

To calculate the height the rocket goes, we can use the equation:

Height = Vy^2 / (2 * gravity) = (25.70 m/s)^2 / (2 * 9.8 m/s^2) = 33.09 meters. To calculate the total time the rocketisinthe air, we can use the equation: Total Time = 2 * Vy / gravity = 2 * (25.70 m/s) / (9.8 m/s^2) =5.25seconds.Tcalculate the distance the rocket travels, we can use the equation:

Distance = Vx * Total Time = (37.15 m/s) * 5.25 seconds = 194.44 meters.