Question

In a sample of 1000 people, 120 are left-handed. Two unrelated people are selected at random without replacement. Find the probability that one is left-handed and the other is right-handed.

A. 0.1152
B. 0.1165
C. 0.1183
D. 0.1200

Answer 1

To find the probability that one person is left-handed and the other person is right-handed, we can use the formula for calculating the probability of two independent events occurring. Given the information provided, the probability is 0.1143.

Step-by-step explanation:

To find the probability that one person is left-handed and the other person is right-handed, we can use the formula for calculating the probability of two independent events occurring:

P(first left-handed, second right-handed) = P(first left-handed) * P(second right-handed)

Given that there are 120 left-handed people out of a sample of 1000, the probability of selecting a left-handed person first is 120/1000. After the first person is selected, there will be 119 left-handed people out of 999. So the probability of selecting a right-handed person second is 119/999. Plugging these values into the formula, we get:

P(first left-handed, second right-handed) = (120/1000) * (119/999) = 0.1143

Therefore, the correct answer is not listed among the given options.