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A rectangle's width is 5 feet less than its length. Write a quadratic function that expresses the rectangle's area in terms of its length.

A. A(l) = l(l)
B. (4(1) = w(w+5))
C. (A(1) = 12 - 5l)
D. (4(1) = 12 + 5l)

1 Answer

3 votes

Final Answer:

The correct quadratic function expressing the rectangle's area in terms of its length is, given by A(l) = w(w + 5). Thus the correct option is B.

Step-by-step explanation:

In the provided options, we need to identify the quadratic function that represents the area of the rectangle in terms of its length. Let's analyze option B: A(l) = w(w + 5).

In this quadratic function, w represents the width and l represents the length of the rectangle. The problem statement states that the width is 5 feet less than the length. Therefore, we can express the width as l - 5 . Substituting this into the quadratic function, we get A(l) = (l - 5)(l - 5 + 5) = (l - 5)(l), which simplifies to A(l) = l(l - 5). This quadratic expression correctly represents the area of the rectangle in terms of its length.

Now, let's consider why the other options are incorrect:

- Option A ( A(l) = l(l) is a simple linear expression and does not account for the given condition that the width is 5 feet less than the length.

- Options C and D are incorrect because they involve unrelated constants (12) and do not correctly represent the relationship between the length and width.

In conclusion, option B (A(l) = w(w + 5)) is the accurate quadratic function that expresses the rectangle's area in terms of its length, considering the given information about the relationship between the length and width of the rectangle.

User Igor Kostin
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