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Find two numbers such that one of them is five times the other, and their difference is 200.

a) 40, 240
b) 50, 250
c) 45, 225
d) 30, 150

User Beatrice
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1 Answer

2 votes

Final answer:

To solve this problem, we can set up a system of equations. One number is five times the other, and their difference is 200. Solving the system, we find that the numbers are 50 and 250.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's call one number x and the other number y. We know that one number is five times the other, so we can write the equation x = 5y. We also know that their difference is 200, so we can write the equation x - y = 200. Substituting the value of x from the first equation into the second equation, we get 5y - y = 200. Simplifying this equation, we get 4y = 200. Dividing both sides by 4, we get y = 50. Substituting the value of y back into the first equation, we get x = 5(50) = 250. Therefore, the numbers are 50 and 250, so the correct answer is b) 50, 250.

User Ray Wurlod
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