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How many real-number solutions does the equation have? - 7x2 + 6x + 3 = 0​

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Answer:

How many real-number solutions does the equation have? - 7x2 + 6x + 3 = 0​

Explanation:

a. B^2-4AC = 36-(-84) = 120.

The discriminant is positive. Therefore, we have 2 real solutions.

b. B^2-4AC = 324-324 = 0. 1 real solution.

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