Question

Calculate the empirical formula of the compound formed when 0.46 g of Cu reacts with 0.12 g of S to form a copper sulfide. Show your work.

Answer 1

The empirical formula of the compound formed when 0.46 g of Cu reacts with 0.12 g of S to form copper sulfide is Cu2S.

Step-by-step explanation:

To calculate the empirical formula of the compound formed when 0.46 g of Cu reacts with 0.12 g of S to form copper sulfide, we need to determine the ratio of the elements present in the compound.

First, we calculate the number of moles of Cu and S using their molar masses:

• Number of moles of Cu = 0.46 g / 63.55 g/mol = 0.00724 mol
• Number of moles of S = 0.12 g / 32.06 g/mol = 0.00374 mol

The ratio of Cu to S is approximately 2:1, so the empirical formula of the compound is Cu2S.