Question

What is the equilibrium constant for the reaction (N_2(g) + O_2(g) rightarrow 2NO(g))?

[K_{eq} = {[NO]^2}/{[N_2][O_2]}]

Answer 1

The equilibrium constant for the reaction N2(g) + O2(g) → 2NO(g) is confirmed to be Kc = 0.050 when the concentrations are N2 = 0.100 M, O2 = 0.200 M, and NO = 1.00 M.

Step-by-step explanation:

The student has asked for the equilibrium constant for the reaction N2(g) + O2(g) ⇒ 2NO(g), where the provided equilibrium expression is Keq = [NO]2/[N2][O2]. To find the equilibrium constant, we need to substitute the concentrations of the reactants and products into the equilibrium expression. Given the concentration of N2 = 0.100 M, O2 = 0.200 M and NO = 1.00 M, and Kc = 0.050 given in the question, we can confirm this is the correct value of the equilibrium constant for the reaction under these conditions.