Final answer:
The probability that the first student chosen is a junior and the second is a sophomore from a Chemistry class of 13 sophomores and 20 juniors is calculated as (20/33) * (13/32), which simplifies to 65/264 or approximately 0.2462. This doesn't match any of the given multiple-choice options.
Step-by-step explanation:
The question asks us to calculate the probability that the first student chosen is a junior and the second is a sophomore from a Chemistry class. There are a total of 33 students (13 sophomores and 20 juniors). The probability of selecting the first student who is a junior is 20/33. After selecting a junior, we are left with 32 students (13 sophomores and 19 juniors), so the probability that the second student chosen is a sophomore is 13/32. To find the total probability of both events happening in sequence, we multiply the two probabilities together: (20/33) * (13/32). When calculated, this gives us an answer of 260/1056, which can be reduced to 65/264.
After performing the calculations, none of the given options a), b), c), or d) matches our result. It's highly possible that there might be an error in this answer or in the provided options. If we revisit our calculation and confirm that 65/264 is accurate, we would then express this as a decimal to get approximately 0.2462.
Since it's crucial to provide an answer only when we are confident it is correct, and in this case, we've discovered that the answer doesn't match any of the provided options, it would be advisable to recheck the calculations or seek further clarification before finalizing an answer.