51.7k views
4 votes
In a box, there are 8 red and 6 blue markers. How many ways can you select 3 markers if there are more blue markers than red markers?

A. 56
B. 84
C. 48
D. 72

1 Answer

3 votes

Final answer:

The number of ways to select 3 markers when there are more blue markers than red markers is 24.

Step-by-step explanation:

The number of ways to select 3 markers when there are more blue markers than red markers can be calculated using a tree diagram. The first set of branches represents the first draw, with 8 ways to draw a blue marker and 3 ways to draw a red marker. The second set of branches represents the second draw, with 8 ways to draw a blue marker and 3 ways to draw a red marker, regardless of the choice on the first draw. Reading down each branch results in the total number of possible outcomes. Counting the outcomes that consist of a blue marker on the first draw and a red marker on the second draw, there are 24 ways. Therefore, the answer is 24 (option C).

User Rvazquezglez
by
8.7k points