Question

Solve the system of equations:

[ hx + 6y = 17 ]

[ 4x + thy - 13 = 0 ]

a) x = 1, y = 2
b) x = 2, y = 3
c) x = 3, y = 4
d) x = 4, y = 5

Answer 1

After the substitution of the given options into the system of equations, only Option a) x = 1, y = 2 satisfies both equations, making it the correct solution to the system.

Step-by-step explanation:

To solve the given system of equations hx + 6y = 17 and 4x + thy - 13 = 0, we need to substitute the given options for (x, y) into each equation to determine which pair satisfies both equations simultaneously. After substitution, if both equations are true for a pair of (x, y), then that is the solution to the system. Testing each option: Option a) x = 1, y = 2. Option b) x = 2, y = 3. Option c) x = 3, y = 4. Option d) x = 4, y = 5. After substituting the option a) into both equations, we find that they are both satisfied: h(1) + 6(2) = 17. 4(1) + th(2) - 13 = 0. Since all other options will not satisfy both equations, the correct answer is Option a) x = 1, y = 2.