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Turkey the Pigeon travels the same distance of 40 miles in 5 hours against the wind as he does traveling 4 hours with the wind in local skies. What is the rate of Turkey the Pigeon in still air and the rate of the wind?

a) Rate of Turkey the Pigeon in still air: 8 mph, Rate of the wind: 4 mph
b) Rate of Turkey the Pigeon in still air: 10 mph, Rate of the wind: 6 mph
c) Rate of Turkey the Pigeon in still air: 12 mph, Rate of the wind: 8 mph
d) Rate of Turkey the Pigeon in still air: 15 mph, Rate of the wind: 5 mph

User Salavert
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Final Answer:

Turkey the Pigeon travels the same distance of 40 miles in 5 hours against the wind as he does traveling 4 hours with the wind in local skies The rate of Turkey the Pigeon in still air and the rate of the wind is Rate of Turkey the Pigeon in still air: 10 mph, Rate of the wind: 6 mph.Thus the option b) Rate of Turkey the Pigeon in still air: 10 mph, Rate of the wind: 6 mph is correct.

Step-by-step explanation:

Let the rate of Turkey the Pigeon in still air be T mph, and the rate of the wind be W mph. When traveling against the wind, the effective speed is

T−W, and with the wind, it is T+W. The formula for distance, Distance=Speed×Time, can be applied to both scenarios.

Given that Turkey the Pigeon travels 40 miles in 5 hours against the wind, we have the equation 40=5×(T−W). Similarly, for traveling with the wind in 4 hours, the equation is 40=4×(T+W).

Solving these simultaneous equations, we find that T=10 mph and W=6 mph. Therefore, the correct answer is option b), as it accurately represents the rate of Turkey the Pigeon in still air and the rate of the wind.

Understanding and solving rate problems involve setting up equations based on the given conditions. In this case, recognizing the relationship between speed, time, and distance allows for the formulation of equations that, when solved, provide the rates of Turkey the Pigeon in still air and the wind.

Thus the option b) Rate of Turkey the Pigeon in still air: 10 mph, Rate of the wind: 6 mph is correct.

User Joe Healey
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