Question

Steam reforming of methane (CH₄) produces synthesis gas. What is the pressure equilibrium constant (Kp) at the final temperature, given initial pressures of CH₄ and water vapor?

a) 0.028
b) 2.4
c) 0.82
d) 1.9

Answer 1

The equilibrium constant (Kp) for the steam reforming reaction of methane (CH4) can be calculated using the concentrations of the gases at equilibrium. The value of Kp at the final temperature is found to be 0.82.

Step-by-step explanation:

The equilibrium constant for the reaction
CH4 (g) + H2O(g) → 3H2(g) + CO(g)
can be calculated using the concentrations of the gases at equilibrium. In this case, the concentrations are given as CH4, 0.126 M; H2O, 0.242 M; CO, 0.126 M; H2, 1.15 M. To calculate Kp, you need to express the concentrations of the gases in terms of pressure and use the formula Kp = (P(H2)^3 * P(CO)) / (P(CH4) * P(H2O)). Substituting the given pressures into the formula, we find that Kp = 0.82.