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This skateboarding child only needs 8 seconds to make it the 28 meters down the length of a basketball court. What is the average velocity (in m/s) required to make this happen?

User Manoj Hans
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Final answer:

The average velocity required for the skateboarding child to cover 28 meters in 8 seconds is 3.5 m/s.

Step-by-step explanation:

The student is asking about the average velocity required for a skateboarding child to travel the length of a basketball court, which is 28 meters, in 8 seconds. To calculate the average velocity, we use the formula: average velocity = total distance / total time.

In this case, the total distance is 28 meters and the total time is 8 seconds.

So the calculation would be: average velocity = 28 meters / 8 seconds = 3.5 meters per second (m/s).

User Sednus
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