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Write the equation of the line through the given point. Use slope-intercept form .Given points (-3,3); perpendicular to y= - 5/3X-4

a) y= 5/3x+2
b) y=-3/5x+4
c) y=− 5/3x+2
d) y= 3/5 x−4

User Syeberman
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1 Answer

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Final answer:

The equation of the line through the given point (-3,3) and perpendicular to y=-5/3x-4 is y=3/5x-4.

Step-by-step explanation:

The equation of a line in slope-intercept form is given by y = mx + b, where m is the slope and b is the y-intercept. We are given that the line is perpendicular to y = -5/3x - 4. The slope of the given line is -5/3. The slope of a line perpendicular to it will be the negative reciprocal, which is 3/5.

The given point is (-3,3). We can substitute this point and the slope into the slope-intercept equation to find the equation of the line. Plugging in the values, we get y = 3/5x - 4.

Therefore, the correct equation of the line through the given point and perpendicular to y = -5/3x - 4 is y = 3/5x - 4.

User Chew Socks
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