Final answer:
Jeremiah can organize his 13,566 M&M's into 135 groups of hundreds, with 66 M&M's left over, resulting in 135 being the most groups he can make.
Step-by-step explanation:
Jeremiah has 13,566 M&M's and wants to organize them into groups of hundreds. To find the most groups of hundreds he can make, we divide the total number of M&M's by 100 and take the whole number part of the quotient, ignoring the remainder. If we divide 13,566 by 100, we get 135 with a remainder of 66. Therefore, Jeremiah can make 135 groups of 100 M&M's with 66 M&M's left over, making the correct answer A) 135 groups.