Question

27 = 3c - 3(6-2c)
A) c= 5
B) c= -5
C) c= -15
D) c= 15

Answer 1

To solve the equation 27 = 3c - 3(6-2c), distribute the -3 into the parentheses, combine like terms, and then isolate c by adding 18 and dividing by 9, yielding c = 5, which is choice A.

Step-by-step explanation:

The student is asking to solve the equation 27 = 3c - 3(6-2c). First, we will distribute the -3 inside the parentheses:

27 = 3c - 3×6 + 3×2c

27 = 3c - 18 + 6c

Combine like terms:

27 = 9c - 18

Next, add 18 to both sides to isolate the term with the variable c:

27 + 18 = 9c

45 = 9c

Now, divide both sides by 9 to solve for c:

c = 45 / 9

c = 5

So the value of c that satisfies the equation is 5, which corresponds to choice A.