Question

There are three consecutive even integers. If twice the first integer added to the second is 268226, find all three integers.

a. 44442, 44444, 44446
b. 56130, 56132, 56134
c. 70798, 70800, 70802
d. 82306, 82308, 82310

Answer 1

To find the three consecutive even integers, use the given equation 2x + (x + 2) = 268226. By solving this equation, we find that the three integers are 89408, 89410, and 89412.

Step-by-step explanation:

To find the three consecutive even integers, let's represent the first even integer as x.

The second consecutive even integer can be represented as (x + 2), and the third consecutive even integer can be represented as (x + 4). We are given that twice the first integer added to the second is 268226.

So, we can write the equation as 2x + (x + 2) = 268226. Solving this equation will help us find the value of x and subsequently, the three integers.

Combining like terms, we get 3x + 2 = 268226. Subtracting 2 from both sides gives us 3x = 268224. Dividing both sides by 3 gives us x = 89408.

Therefore, the three consecutive even integers are 89408, 89410, and 89412.